Integrand size = 10, antiderivative size = 56 \[ \int \frac {x^3}{\arccos (a x)^2} \, dx=\frac {x^3 \sqrt {1-a^2 x^2}}{a \arccos (a x)}-\frac {\operatorname {CosIntegral}(2 \arccos (a x))}{2 a^4}-\frac {\operatorname {CosIntegral}(4 \arccos (a x))}{2 a^4} \]
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Time = 0.04 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {4728, 3383} \[ \int \frac {x^3}{\arccos (a x)^2} \, dx=-\frac {\operatorname {CosIntegral}(2 \arccos (a x))}{2 a^4}-\frac {\operatorname {CosIntegral}(4 \arccos (a x))}{2 a^4}+\frac {x^3 \sqrt {1-a^2 x^2}}{a \arccos (a x)} \]
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Rule 3383
Rule 4728
Rubi steps \begin{align*} \text {integral}& = \frac {x^3 \sqrt {1-a^2 x^2}}{a \arccos (a x)}+\frac {\text {Subst}\left (\int \left (-\frac {\cos (2 x)}{2 x}-\frac {\cos (4 x)}{2 x}\right ) \, dx,x,\arccos (a x)\right )}{a^4} \\ & = \frac {x^3 \sqrt {1-a^2 x^2}}{a \arccos (a x)}-\frac {\text {Subst}\left (\int \frac {\cos (2 x)}{x} \, dx,x,\arccos (a x)\right )}{2 a^4}-\frac {\text {Subst}\left (\int \frac {\cos (4 x)}{x} \, dx,x,\arccos (a x)\right )}{2 a^4} \\ & = \frac {x^3 \sqrt {1-a^2 x^2}}{a \arccos (a x)}-\frac {\operatorname {CosIntegral}(2 \arccos (a x))}{2 a^4}-\frac {\operatorname {CosIntegral}(4 \arccos (a x))}{2 a^4} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.89 \[ \int \frac {x^3}{\arccos (a x)^2} \, dx=-\frac {-\frac {2 a^3 x^3 \sqrt {1-a^2 x^2}}{\arccos (a x)}+\operatorname {CosIntegral}(2 \arccos (a x))+\operatorname {CosIntegral}(4 \arccos (a x))}{2 a^4} \]
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Time = 0.65 (sec) , antiderivative size = 54, normalized size of antiderivative = 0.96
method | result | size |
derivativedivides | \(\frac {\frac {\sin \left (2 \arccos \left (a x \right )\right )}{4 \arccos \left (a x \right )}-\frac {\operatorname {Ci}\left (2 \arccos \left (a x \right )\right )}{2}+\frac {\sin \left (4 \arccos \left (a x \right )\right )}{8 \arccos \left (a x \right )}-\frac {\operatorname {Ci}\left (4 \arccos \left (a x \right )\right )}{2}}{a^{4}}\) | \(54\) |
default | \(\frac {\frac {\sin \left (2 \arccos \left (a x \right )\right )}{4 \arccos \left (a x \right )}-\frac {\operatorname {Ci}\left (2 \arccos \left (a x \right )\right )}{2}+\frac {\sin \left (4 \arccos \left (a x \right )\right )}{8 \arccos \left (a x \right )}-\frac {\operatorname {Ci}\left (4 \arccos \left (a x \right )\right )}{2}}{a^{4}}\) | \(54\) |
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\[ \int \frac {x^3}{\arccos (a x)^2} \, dx=\int { \frac {x^{3}}{\arccos \left (a x\right )^{2}} \,d x } \]
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\[ \int \frac {x^3}{\arccos (a x)^2} \, dx=\int \frac {x^{3}}{\operatorname {acos}^{2}{\left (a x \right )}}\, dx \]
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\[ \int \frac {x^3}{\arccos (a x)^2} \, dx=\int { \frac {x^{3}}{\arccos \left (a x\right )^{2}} \,d x } \]
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none
Time = 0.27 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.89 \[ \int \frac {x^3}{\arccos (a x)^2} \, dx=\frac {\sqrt {-a^{2} x^{2} + 1} x^{3}}{a \arccos \left (a x\right )} - \frac {\operatorname {Ci}\left (4 \, \arccos \left (a x\right )\right )}{2 \, a^{4}} - \frac {\operatorname {Ci}\left (2 \, \arccos \left (a x\right )\right )}{2 \, a^{4}} \]
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Timed out. \[ \int \frac {x^3}{\arccos (a x)^2} \, dx=\int \frac {x^3}{{\mathrm {acos}\left (a\,x\right )}^2} \,d x \]
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